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Priyapatel

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Rajasthan Board - Hindi Medium NCERT solutions for Class 10.Get free online study material for Class 10.Find NCERT solutions textbook questions and answers and download NCERT books from Zigya Book-Store.
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Let the speed of cyclist be x kmph   ...(i)and its time to cover a distance be y hours.              = (x)  X  (y) kmDistance covered by cyclist is xy km Distance covered by jogger = (xy /2) kmTime  = 2y hoursFrom (i) and (ii)Ratio of their speeds = 
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RuBisCo enzymes acts as both carboxylase and oxygenase. It carries out more carboxylation in the C4 plants as these plants have special mechanism that increases the concentration of the CO2 at the enzyme site. There is no photorespiration in the C4 plants and thus oxygen does not bind to the RuBisCo enzyme. All this minimizes the oxygenase activity of the enzyme and increase the carboxylase activity. 
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sin 3A = cos (A - 26°).⇒ cos (90° - 3A) = cos (A - 26°)⇒  90° - 3A = A - 26°⇒  90° + 26° = 3A + A⇒   4A = 116
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Given, ionic radius of cation (A+) =0.98 x 10-10mIonic radius of anion (B-)=1.81 x 10-10mtherefore,The coordination number of each ion in AB =?Now we have.If radius ratio range is in between 0.441-0.732 ion would have an octahedral structure with coordination number six.
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As we know that kinetic energy of an electron is KE ∝ (Z/n)2 when the electron makes the transition from an excited state of the ground state then n, decreases and KE increases. We know that PE is lowest for the ground state. As TE=- KE and TE also decreases.